How to print the multiple files while doing the pick-up.

chaky · Post by **chaky** » Tue Jul 12, 2016 9:10 am

Hello,

To give the background, I am a mainframe application programmer. We have SFTPs in system with both the flavors (single file pick-up or multiple file pick-up). I understand the single file pick-up is a straight forward GET command, but for multiple file Pick-up below code is required in COZBATCH. By running the code I understood that below "get" and "rm" commands go in loop (means a file is selected based on a pattern, that file gets into the dataset and then gets deleted), but if someone can help me understand below awk programming, that would be great. Also I want to display the file in job output just before removing it, so I did try "!cat" between "get" and "rm". Seems like it works good on a single file and doesn't work in below, do we have any other option to try by which I can achieve displaying the file just before removing it?

Code: Select all

{
$coz_bin/cozsftp $ssh_opts -b- $r_user@$r_server <<EOB
ls -l $r_pattern
EOB
} | awk '
BEGIN {
  print "lzopts " ENVIRON["zopts"]
  skip = 1
}
{
  if (skip == 1) {
    if ($1 == "cozsftp>") skip = 0
    next;
  }
  print "get " $9 " //DD:GETFILE"
  print "rm " $9
}' | $coz_bin/cozsftp  $ssh_opts -b- $r_user@$r_server

Any help or additional information would be great.

Thanks and Regards,
Chaky.