What exactly does the //! option provide? I have read the DOC and I can't see the difference between specifying // vs. //!. Could you provide better examples?
Jerry Roman
Dataset Name with //!
Re: Dataset Name with //!
Jerry -
Just to double-check, have you looked at this?
http://dovetail.com/docs/sftp/dsn-determination.html
Basically, the //! syntax means that the dataset is always considered to be a dataset, even if there exists other datasets at lower "levels" below that dataset. It serves to disambiguate references that could be considered as either "directories" or "files". It is necessary to make z/OS dataset structures map into a POSIX directory model.
Just to double-check, have you looked at this?
http://dovetail.com/docs/sftp/dsn-determination.html
Basically, the //! syntax means that the dataset is always considered to be a dataset, even if there exists other datasets at lower "levels" below that dataset. It serves to disambiguate references that could be considered as either "directories" or "files". It is necessary to make z/OS dataset structures map into a POSIX directory model.